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[NOTES/QM-06007] Compatible Dynamical Variables

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The question of simultaneous measurement of two dynamical variables is analysed. Starting from the postulates it is argued that two variables can be measured simultaneously if and only of they commute. This result generalizes to simultaneous measurement of several dynamical variables.


 

Let  \(A\) and \(B\) be two dynamical variables, \(\hat{A}, \hat{B}\) be the corresponding operators, \(\alpha_j, j=1,2,\ldots\) and \(\beta_k, k=1,2,\ldots\) be their eigenvalues. Let us assume that \(A\) and \(B\) can be measured simultaneously. This means there are states in which these variables have definite values \(\alpha_j, \beta_k, j,k =1,2,\ldots\).The corresponding vectors \(\ket{\alpha_j,\beta_k}\) must then be simultaneous eigenvectors of the the two operators. \begin{equation} \hat{A}\ket{\alpha_j,\beta_k} =\alpha_j\ket{\alpha_j,\beta_k}, \qquad \hat{B}\ket{\alpha_j,\beta_k} =\beta_k\ket{\alpha_j,\beta_k} \end{equation}

In order that the probability of getting pair of values \(\alpha_j,\beta_k\) for all pairs \(j,k\) be given by the postulate III, it should be possible to write an arbitrary vector \(\ket{\psi}\) as linear combination of these vectors \( \mathscr{B}=\{\ket{\alpha_j,\beta_k}| j=1,2,..., k=1,2,... \}\) and these states must form a basis.Now it is easy to show that the action of \(\hat{A}\hat{B}-\hat{B}\hat{A}\) on
each of these vectors in the set \(\mathscr{B}\) is zero. In fact
\begin{eqnarray}
  \big(\hat{A}\hat{B} - \hat{B} \hat{A}\big)\ket{\alpha_j,\beta_k}
  &=& \hat{A}\hat{B} \ket{\alpha_j,\beta_k}- \hat{B}
                   \hat{A}\ket{\alpha_j,\beta_k}\\
  &=& \hat{A}\beta_k\ket{\alpha_j,\beta_k} -
            \hat{B}\alpha_j\ket{\alpha_j,\beta_k}\\
   &=& \alpha_j\beta_k  \ket{\alpha_j,\beta_k} - \beta_k\alpha_j
           \ket{\alpha_j,\beta_k}\\
   &=& 0.
\end{eqnarray}
Thus we have proved that the action of  commutator \([\hat{A},\hat{B}]\) on every element of  basis \(\mathscr{B}\) results in zero. This implies that \([\hat{A},\hat{B}]=0\) and the two operators \(\hat{A}, \hat{B}\) must commute.

Conversely, if two hermitian operators commute, one can select a basis of orthonormal vectors which are simultaneous eigenvectors of the two operators.The above considerations generalize to several dynamical variables.

A set of operators \(\{\hat{A}_k,k=1,2,\ldots\}\) is called commuting set if every pair of operators \( \hat{A}_\ell, \hat{A}_m\) commute, i.e.
\begin{equation}
  [\hat{A}_\ell, \hat{A}_m]=0 \quad \text{for all pairs} \ell, m.
\end{equation}

A set of dynamical variables \(\{A_k, k=1,2,\ldots\}\) is called a compatible set if the corresponding set of operators  \(\{\hat{A}_k, k=1,2,\ldots\}\) is a commuting set of operators.

 Remember
`A set of dynamical variables an be  can be measured simultaneously if and only if they commute pairwise. In other words they should form a compatible set.''

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