Compute average of kinetic and potential energies \[ \text{K.E.} = \frac{p^2}{2m},\qquad \text{P.E.}= \frac{1}{2}m\omega^2x^2.\] in the \(n^\text{th}\) excited state and show that the the average of total energy is \(\frac{1}{2}\hbar \omega\).
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4727:Diamond Point
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