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\begin{equation}
\frac{\mu_0}{4\pi} =10^{-7} \text{henry/meter}
\end{equation}
\begin{eqnarray}
\epsilon_0 &=&\frac{10^7}{4\pi c^2} \, \frac{\text{coulomb}^2 \text{second}^2}{\text{kilogram (meter)}^3}\\
&\approx& \frac{1}{36 \pi\times 10^9} \frac{1 \text{farad}}{1 \text{meter}}.
\end{eqnarray}
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