The tension $\tau$ in an elastic rubber band is given by $$ \tau\,=\,aT\left(\frac{L}{L_0(T)}-\,\left(\frac{L_0(T)}{L}\right)^2\right),$$ where $a$ is a constant, $L_0(T)$is the unstretched length at zero tension, and is a function of temperature only.
- Write the first law using the work done when it is elongated and gets a supply of heat. ( Be careful of signs!)
- Use the first law to write $dF$, where $F$ is the free energy of the rubber band.
- Solve for the free energy $F$ and show that $$ F(T,L)\,-\,F(T,L_0(T))\,=\,aT\left(\frac{L^2}{2L_0(T)}\,+\,\frac{L_0(T)^2}{L^2}\,-\,\frac{3L_0(T)}{2}\right)$$ and the entropy $S$ $$ S(T,L)\,-\,S(T,L_0(T))\,=\,a\left(\frac{3L_0}{2}\,-\,\frac{L_0^2}{L}\,-\,\frac{L^2}{2L_0}\right)\,-\,aT\left(\frac{3}{2}\,-\,\frac{2L_0}{L}\,+\,\frac{L^2}{2L_0^2}\right)\frac{dL_0(T)}{dT} $$
- Find the heat $Q$ transferred to the elastic band when it is stretched from $L_0$ to $L$ isothermally.
- Show that $$ \left(\frac{\partial T}{\partial L}\right)_S \,=\,\frac{aTL_0^2}{c_LL^2}\left(-1\,+\,\left(\frac{L}{L_0}\right)^3\,+\,\frac{Ta}{L_0}\frac{dL_0}{dT}\left(2\,+\,\left(\frac{L}{L_0}\right)^3\right)\right)$$ where $$c_L\,=\,\left(\frac{DQ}{\partial T}\right)_L.$$
Exclude node summary :
n
Exclude node links:
0
4727:Diamond Point, 5017:TH-HOME
0