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[YMP/EM-02010] Electric Field of Overlapping Uniformly Charged Spheres

Node id: 6023page
 

Problem

Two spheres, each of radius $R$ and carrying charge densities $+\rho$ and $-\rho$ respectively, are placed so that they partially overlap. The separation between the centers of the spheres is $D$. Show that the field in the region of overlap is constant and find its value.
kapoor's picture 23-12-04 05:12:08 n

[YMP/EM-02009] Electric Field of a Uniformly Charged Sphere

Node id: 6022page
 

Show that the electric field of a uniformly charged sphere, radius \(R\), total charge \(Q\) has the magnitude given by\[E= \begin{cases}  E_0 x &   x< 1  \\ E_0/x^2 &  x>1 \end{cases}\]where \(E_0= \dfrac{Q}{4\pi\epsilon_0 R^2 }\)   and \(x=\dfrac{r}{R}\).

kapoor's picture 23-11-23 22:11:47 n

[YMP/EM-02008] Electric Field Due to a Dipole

Node id: 6013page

A dipole is a system of two equal and opposite charges separated by a distance. Its electric field is computed and the field at large distances depends only on the dipole moment, defined as the product of the charge and separation between the charges.

While dipole is a system of two charges, the concept of dipole moment is defined and is useful for any system of charges  with total zero charge.

kapoor's picture 23-11-23 22:11:57 n

[YMP/EM-02007] Electric Field of a Uniformly Charged Spherical Shell

Node id: 6020page

We will show that for a uniformly charged sphere, radius \(a\) and charge \(Q\),

the electric field is given by
\begin{equation}
 \vec E =  \begin{cases} 0 & \text{if } r<a\\
     \frac{Q}{4\pi\epsilon_0 R^2 }  & \text{if } r > a
 \end{cases}
\end{equation}
  
kapoor's picture 23-12-18 12:12:25 n

[YMP/EM-02006] Electric Field due to a Uniformly Charged Disk

Node id: 6019page

We will show that the electric field  due to a uniformly charged disk at a point on the axis of the disk is given by

 \begin{eqnarray}
E_z &=&\frac{2Qz}{a^2 4\pi\epsilon_0}\Big[1-\frac{z}{(z^2+a^2)^{1/2}}\Big]\\ \label{eq11A}
\end{eqnarray}

At a point on the axis of the disk, only the \(z\) component is non-zero, the other two components vanish, \(E_x=E_y\).

 

 

 

kapoor's picture 23-12-18 12:12:23 n

[YMP/EM-02005] Field due to a Uniformly Charged Ring

Node id: 6018page

The electric field due to a charged ring, at a point, \(P\) on its axis,  is computed using Coulomb's law. We will show that the electric field of uniformly charged ring, radius \(R\), at a  point on the axis of the ring,  is given by

 \begin{equation}
 \vec E = \frac{qz}{4\pi\epsilon_0(z^2+r_0^2)^{3/2}} \, \hat k.
\end{equation}
where \(q\) is the total charge and \(z\) is the distance if field point from the center of the ring. 
 
kapoor's picture 23-12-18 11:12:07 n

[YMP/EM-02004] Electric Field due to a Line with Uniform Charge Density

Node id: 6016page

Let \(AB\) be a line charge with charge per unit length $\lambda$, which is given to be uniform. The field is to be computed at a point \(P\),. Let \(p\) be the perpendicular distance of \(P\) from the line \(AB\). let \(\alpha, \beta\) be the angles as shown in the figure. Electric field will be calculated at a general point \(P\), the corner point \(C\) and the middle point \(M\) as shown in figure below.

kapoor's picture 23-11-23 22:11:35 n

[YMP/EM-02003] Dipole Moment of Overlapping Spheres

Node id: 6015page
Two spheres each of radius $R$ are placed so that they partially overlap. The charge densities in the overlap region is zero. Outside the overlap region but inside the spheres the charge densities in the two non overlapping   regions are $+\rho$ and $-\rho$, respectively, as shown in figure. The charge density in the overlap region will be zero. The separation between the centers of the spheres is $D$.

Overlapping uniformly charged spheres

  1. Guess the value of the dipole moment?
  2. Compute the dipole moment of the system and check the correctness of the expression you guessed.
  3. How will the dipole moment change if the two spheres equal and opposite total charges but have different radii \(a,b, a \ne b\).
kapoor's picture 23-11-23 22:11:53 n

[YMP/EM-01005] Alpha Particle in Magnetic Field --- Circular Orbit

Node id: 5902page
kapoor's picture 23-12-12 11:12:36 n

[YMP/EM-01004] Solved Problem

Node id: 5901page
kapoor's picture 23-05-11 23:05:26 n

[YMP/EM-01002] inkjet Printer

Node id: 5900page
kapoor's picture 23-05-11 23:05:45 n

[YMP/EM-01001] Motion of Charged Particle in Electric Field

Node id: 5898page
kapoor's picture 23-05-06 18:05:27 y

[YMP/CV-05001] Elementary Functions --- Solved Examples

Node id: 5621page
AK-47's picture 22-08-06 19:08:02 n

[YMP/CM-08003] Coriolis Force --- Focault Pendulum

Node id: 6308page

The plane of oscillation of a simple pendulum is rotates due to Coriolis force. It is shown that the angular velocity of rotation is equal and opposite to the Earth's angular velocity. This result has the interpretation that the pendulum keeps oscillating in a fixed plane as seen from the frame fixed in stars. This is expected

kapoor's picture 24-06-19 17:06:27 n

[YMP/CM-08002] How good are different frames as inertial frames

Node id: 6307page
kapoor's picture 24-06-19 17:06:43 n

[YMP/CM-08001] Coriolis Force --- Sideways deflection of a freely falling body

Node id: 6306page

A body falling under the earth's gravitational field experiences a side ways deflection due to Coriolis force. An expression for this deflection is obtained and numerical values are estimated.

kapoor's picture 24-06-19 17:06:02 n

[XMP/QM-13001] Short Examples --- Nature of Energy Spectrum

Node id: 6327page

We give several examples to explain how to obain the nature of energy spectrum without solving the problem completely.

kapoor's picture 24-07-11 17:07:31 n

[XMP/QM-06001] Short Examples --- States of a system; Id::

Node id: 1961page
kapoor's picture 22-05-06 18:05:12 n

[XMP/QFT-04001] Short Example --- Microcausality

Node id: 3554page
kapoor's picture 22-05-06 18:05:01 n

[XMP/CM-04004] Short Examples --- Computing Hamiltonian and Lagrangian

Node id: 6292page
kapoor's picture 24-06-11 20:06:08 n

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