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[NOTES/QM-20007] A First Look at the He Atom Energy LevelsNode id: 4851page$\newcommand{\DD}[2][]{\frac{d^2 #1}{d^2 #2}}$ $\newcommand{\matrixelement}[3]{\langle#1|#2|#3\rangle}$ $\newcommand{\PP}[2][]{\frac{\partial^2 #1}{\partial #2^2}}$ $\newcommand{\dd}[2][]{\frac{d#1}{d#2}}$ $\newcommand{\pp}[2][]{\frac{\partial #1}{\partial #2}}$ $\newcommand{\average}[2]{\langle#1|#2|#1\rangle}$ $\newcommand{\ket}[1]{\langle #1\rangle}$ qm-lec-20007
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22-03-05 08:03:03 |
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[NOTES/EM-09002]-Understanding Electromagnetic InductionNode id: 5723pageIn this section examples are given to show that the flux rule is not always applicable.
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22-08-24 15:08:21 |
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21Th-ProbSet5Node id: 4998page |
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21-12-04 13:12:34 |
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[QUE/SM-02006] SM-PROBLEMNode id: 5148pageConsider a 2 dimensional phase space ( $q,p$) with a rectangular region defined by four corners as shown.

If the region ABCD is the phase space region at time time t = 0 , find the region $A'B'C'D'$ at time t given the Hamiltonian is $$ H\,=\,\frac{p^2}{2m}\,-\, m a q $$ and explicitly verify that the area is constant. Take the coordinates of A,B,C and D as $(q_A,p_A)\,,\,(q_B,p_A)\,,\,(q_B,p_C)$ and $(q_A,p_C)$ respectively
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22-01-14 10:01:19 |
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[QUE/TH-06014] TH-PROBLEMNode id: 5209page
- [(a)]~ Derive relations similar to $Pv^{\gamma}=$ const., $\theta v^{\gamma-1}=$ const. for a Van der Waals gas.\\
- [(b)]~ Compute the work done in a reversible adiabatic expansion by direct evaluation of $\int P dv$ and by the use of energy equation \begin{eqnarray} u = C_v\theta -~{a\over v}~+ \text{const.}&\hfill{[4+4]} \end{eqnarray}
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22-01-23 11:01:56 |
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[2019EM/QUIZ-04#Solu]Node id: 5356page Electrodynamics March 11, 2019
Quiz-IV
In case of a charge distribution having symmetry about \(z\)-axis,
\(Q_{xy}=Q_{yz}=Q_{zx}=0\) and \(Q_{yy}=Q_{xx}\) Also trace \(Q_{xx}+Q_{yy}+Q_{zz}\) is always zero. Thus the quadrupole moment tensor can be specified by a single number \(Q= 2(Q_{zz}-Q_{xx})\). Calculate \(Q\) for six equal charges placed on corners of a regular hexagon of sides \(a\).
The definition of quadrupole moment tensor components is \begin{eqnarray} Q_{xx} &=&\frac{1}{2} \sum_\alpha Q_\alpha (3x^2_\alpha - r^2_\alpha)\\ Q_{yy} &=& \frac{1}{2} \sum_\alpha Q_\alpha (3y^2_\alpha - r^2_\alpha)\\ Q_{zz}&=& \frac{1}{2} \sum_\alpha Q_\alpha (3z^2_\alpha - r^2_\alpha) \end{eqnarray} In this case \(Q_{xz}=Q_{yz}=0\) because all charges are in \(XY\) plane \((z=0)\). Also \(Q_{xy}=0\) due to symmetry reflection symmetry in the \(X, Y\) axes. For all the charges \(z=0, r=a\). Hence \begin{equation*} \sum_{\alpha=1}^6 z^2=0 \qquad \sum_{\alpha=1}^6 r^2= 6a^2 \end{equation*} For four charges \(x^2= \frac{3a^2}{4}\) and for two charges \(x=0\). Therefore \begin{equation*} \sum_{\alpha=1}^6 3 x^2 = 9a^2 \end{equation*} Thus we get \begin{eqnarray} Q_{xx} &=& \frac{1}{2} \sum_\alpha Q_\alpha (3x^2_\alpha - r^2_\alpha)= Q (9a^2 - 6a^2) = 3Qa^2 \\ Q_{zz} &=& \frac{1}{2} \sum_\alpha Q_\alpha (3z^2_\alpha - r^2_\alpha)= - 6Qa^2 \end{eqnarray} and the final answer is \[Q= 2(-6Qa^2- 3Qa^2) = -18 Qa^2.\]
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22-04-04 14:04:19 |
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[2018EM/Final-B-Sol]Node id: 5420page |
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22-06-21 06:06:32 |
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[LECS/EM-03005] Maxwell's Equations for ElectrostaticsNode id: 6135pageThe Maxwell's equations for electrostatic are derived from Coulomb's law which has been formulated based on experiments. This provides initial experimental evidence for the Maxwell's equations. We discuss two applications of Maxwell's equations. The first result is that the electric field inside an empty cavity in conductors is proved to be zero. The second result is an expression for electric stress tensor is derived. The surface integral of the electric tensor gives the force on charge distribution.
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24-03-30 05:03:52 |
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[NOTES/EM-02001] -Coulomb’s Law and Electric FieldNode id: 5564pageCoulomb’s law is stated for electric field of a point particle. For several point charges the field is obtained as a vector sum of the fields of individual charges
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23-10-07 05:10:39 |
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Classical Theories RevisitedNode id: 4638page |
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21-09-12 14:09:40 |
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[NOTES/EM-03003]-Maxwell's Equations from Coulomb's Law Node id: 5637pageStarting with the Gauss law and using divergence theorem of vector calculus we derive Maxwell's first equation $\nabla\cdot \vec{E}= \rho/\epsilon_0$.
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23-10-18 08:10:34 |
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[NOTES/QM-17001] Angular Momentum in Quantum Mechanics --- Summary of results Node id: 4813page$\newcommand{\DD}[2][]{\frac{d^2 #1}{d^2 #2}}$ $\newcommand{\matrixelement}[3]{\langle#1|#2|#3\rangle}$ $\newcommand{\PP}[2][]{\frac{\partial^2 #1}{\partial #2^2}}$ $\newcommand{\dd}[2][]{\frac{d#1}{d#2}}$ $\newcommand{\pp}[2][]{\frac{\partial #1}{\partial #2}}$ $\newcommand{\average}[2]{\langle#1|#2|#1\rangle}$ qm-lec-17001
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22-03-07 19:03:01 |
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[NOTES/ME-14002]-Levi-Civita $\epsilon$ and Kronecker $\delta$ symbols as tensorsNode id: 5697page |
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22-08-16 14:08:18 |
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[NOTES/EM-11001]-Electromagnetic Potentials in ElectrodynamicsNode id: 5753page
The vector and scalar potentials are defined in terms of the fields. Using the Maxwell's equations the wave equation for the potentials are derived in the Lorentz gauge.
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23-03-03 21:03:15 |
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Quantum Information and Quantum Computing --- Notes for Lectures and Problems [QIQC-MIXED-LOT]Node id: 5064collection |
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21-12-30 22:12:13 |
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[QUE/TH-08003] TH-PROBLEMNode id: 5183page $$pV\,=\,A(T)\,+\,B(T)p\,+\,C(T)p^2 $$ Find $C_p(T,p)$ in terms of $C_p(T,p_0)$ and $p\,,\,p_0$ ( initial and the final pressures) and $A(T)\,,\,B(T)\,,\,C(T)$ and their derivatives with respect to temperature $T$. [ Write an appropriate expression for $$\frac{\partial C_p}{\partial p} $$ and use it to obtain $C_p$]
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22-01-14 13:01:49 |
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[2013EM/HMW-13]Node id: 5387page |
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22-04-17 14:04:02 |
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[2003SM/LNP-12] Lecture-12--Applications of canonical ensembleNode id: 5537pageThe canonical partition function for an ideal gas is computed and ideal gas equation is derived. A measurement of the Boltzmann constant k is discussed using effusion of gas molecules through a hole. Distribution function of molecules in presence of gravity is as function of height is derived.
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22-07-07 07:07:20 |
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[1998TH/LNP-31]-Node id: 5601page |
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22-07-17 19:07:18 |
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[NOTES/QM-11002] Probability ConservationNode id: 4730page$\newcommand{\DD}[2][]{\frac{d^2 #1}{d^2 #2}}\newcommand{\matrixelement}[3]{\langle#1|#2|#3\rangle}\newcommand{\PP}[2][]{\frac{\partial^2 #1}{\partial #2^2}}\newcommand{\dd}[2][]{\frac{d#1}{d#2}}\newcommand{\pp}[2][]{\frac{\partial #1}{\partial #2}} \newcommand{\average}[2]{\langle#1|#2|#1\rangle} \newcommand{\Label}[1]{\label{#1}}$
Starting from the time dependent Schr\"{o}dinger equation, an equation of continuity \[{\partial\rho\over\partial t} + \vec{\nabla}.\vec{j}=0\] is derived. Physical interpretation of the continuity equation is given in analogy with charge conservation in electromagnetic theory. The equation of continuity represents conservation of probability in quantum mechanics.
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24-06-23 18:06:03 |
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